jqGrid: Error: Invalid XML -
i have jqgrid filled custom xml response server. managed run datatype: "xmlstring", when xml string hard-coded locally, managed run when xml response jqxhr.responsetext, , pass xml string, still using datatype: "xmlstring", when set datatype: "xml", following error:
an error occured during request: error: invalid xml:
and after error there listed code of html page of that, instead of xml response, seems odd me.
the error happens when set data: data, or data: jqxhr.responsetext, or data: jqxhr.responsexml.
any ideas on one? when using datatype: "xml", should correct thing should pass jqgrid data - data, jqxhr.responsetext, jqxhr.responsexml or member of data?
also benefit of using datatype: "xml", on datatype: "xmlstring"? if don't manage run datatype: "xml", use datatype: "xmlstring" xml coming response, , there issue approach?
p.s. versions: jqgrid v. 4.7.0, jquery v. 2.1.3, firefox v. 39.0 , ie 11.
<!doctype html> <html> <head> <title></title> <meta http-equiv="content-type" content="text/html; charset=utf-8"> var columnnames = [ "user id", "organization", "email" ]; var columnmodels = [ { name: "userid", visibility: "mandatory", index: "userid", width: 100, xmlmap: '>reference[name="logicalmember"]>object[type="logicalmember"]>attribute[name="login"]'}, { name: "organization", index: "organization", xmlmap:'>reference[name="organization"]>object[type="organization"]>attribute[name="name"]' }, { name: "email", index: "email", width: 80, xmlmap:'>reference[name="emailaddresses"]>object[type="emailaddress"]>attribute[name="address"]'}, ]; var filtermodel = [ { id: 'userid', name: 'user id', renderer: 'text' }, { id: 'organization', name: 'organization', renderer: 'text', rendereroptions: { prompt: 'domain*' } } ]; var xmlmapping = {root:"searchresponse", row:'searchresponse>object[type="contact"]', records:"searchresponse[total-found]", repeatitems:false, id : "[id]"} // page initialization //------------------------------------------------------------------ $(document).ready( function() { var searchrequest = createusersearchrequest('', '', '', '', null, '', '', 50, 1); var usersessionid = sessionstorage.getitem("usersessionid"); $.ajax({ type : "post", datatype : "xml", url : "../../../../api/", headers: { "usersessionid": usersessionid, "include_extended_attributes" : false, "clientversion" : "3.0", "clientapplication" : "someapp", "content-type" : "text/xml" }, data : searchrequest }) .done(function (data, textstatus, jqxhr) { var xml = jqxhr.responsetext; // table ---------------------- var table = $("#table"); table.jqgrid( { data : data, datatype: "xml", colnames: columnnames, colmodel: columnmodels, multiselect: true, fixedloadingdiv: true, onselectrow: selectrow, onselectall: selectallrow, columnchooserbuttonvisible: true, // sort config cmtemplate: { sortable: true }, sortname: "userid", sortorder: "desc", onsortcol: applysort, xmlreader: xmlmapping, emptyrecords: false, columnsstatecontextkey: "some.context", fixedtableheader: true }); table.jqgrid('hideloadingbar'); }) .fail(function (data, textstatus, jqxhr) { alert("server error!"); }); }); </script> </head> <body> <div class="grid-content"> <table id="table"></table> </div> </body> </html>
the first thing recommend verifying whether correctly includes jquery , jqgrid on page. should modify text of question , include version information jquery , jqgrid use. important know web browser , in version use tests.
the next thing recommend using fiddler or developer tools of ie/chrome/firefox trace http traffic between server , client. should examine the exact body , headers of server response. should include information in text of question. important is: value have content-type header.
one more thing: should start html page in debugger (press f12 start developer tools , start script debugging). see exact place error "invalid xml" take place. can see call stack , line of jquery or jqgrid executed. it's better if use non-minimized version of jquery , jqgrid tests.
updated: code fragment posted shows use jqgrid in th wrong way. first of misunderstand meaning of datatype parameter.
the options datatype: "xml" or datatype: "json" should used in combination url parameter. datatype: "xml" without loadonce: true means implemented server side paging of data , jqgrid should send url requests load every page of data. don't specified rownum option, default value 20 used. during creating of jqgrid makes request fill grid url. if no url specified request current page made.
the parameter data used jqgrid if use datatype: "local". value of data parameter should array elements represents rows of grid.
so if want load xml data url have use mtype: "post", url: "../../../../api/", datatype: "xml", loadonce: true. if want make request url separately should use datatype: "xml", datastr: data. data can pared xml object or string xml data.
if don't load data static xml file recommend use json instead of xml. it's more both client side , server side.
update 2: can use following options example
datatype: "xml", url : "../../../../api/", loadonce: true, mtype: "post", postdata: searchrequest, ajaxgridoptions: { contenttype: "text/xml", headers: { usersessionid: usersessionid, include_extended_attributes: false, clientversion: "3.0", clientapplication : "someapp" } }
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