dictionary - How to do this list/dict comprehension in python -

i creating python dictionary follows:

d= {i : chr(65+i) in range(4)}

now output of d {0: 'a', 1: 'b', 2: 'c', 3: 'd'}

i have list of keys want follows:

l = [0, 1]

now want create list contains values corresponding these keys , wanted know if there pythonic way using list or dict comprehensions.

i can follows:

[x x in d[0]]

however, not know how iterate on entries of list in setting. tried:

[x x in d[a] in l] # name 'a' not defined [x x in d[for in l]] # invalid syntax

you want iterate on l, use for element in l. stuff in dictionary in left-hand side, in value-producing expression:

[d[element] element in l]

note dictionary mapping consecutive integers starting @ 0 letters isn't efficient; may make list:

num_to_letter = [chr(65 + i) in range(4)]

this still maps 0 'a', 1 'b', etc, without hashing step.

Dil