Converting Java Object to XML in the order of Schema xml -

i have java object

@xmlrootelement public class customer {      private string name;     private list<phonenumber> phonenumbers = new arraylist<phonenumber>();     private string id;     private date startdate;     private date enddate;     public string getname() {         return name;     }     public void setname(string name) {         this.name = name;     }     @xmlelement(name = "phone-number")     public list<phonenumber> getphonenumbers() {         return phonenumbers;     }     public void setphonenumbers(list<phonenumber> phonenumbers) {         this.phonenumbers = phonenumbers;     } } 

i want define schema xml (customer.xsd) should used set order of tags while generating xml, object xml generated should below in different order compared object members order.

<customer>     <startdate></startdate>     <enddate></enddate>     <name></name>     <id></id>     <phonenumbers></phonenumbers>  </customer> 

both marshalling , unmarshalling code should based on same schema xml.

can me how create schema , how achieve ordering??

you have 2 choices:

• in java object can define @xmltype(proporder={<order of elements>}) refer here more details.
• second approach (using xsd), can define xsd this:

<xsd:element name="customer">   <xsd:complextype >        <xsd:sequence>           <xsd:element name="name" type="xsd:string" />           <xsd:element name="id" type="xsd:string" />           <xsd:element name="startdate" type="xsd:string" />           <xsd:element name="enddate" type="xsd:int" />           <xsd:element name="phonenumbers" type="xsd:string" minoccurs="0" maxoccurs="unbounded" />        </xsd:sequence>   </xsd:complextype> </xsd:element> 

in xsd can order elements inside <xsd:sequence> please note, have not tried xsd example, added reference.