java - hibernate: how to select all rows in a table -

i try select * logentry hibernate. insert works fine:

import javax.persistence.entitymanager; import javax.persistence.entitymanagerfactory; import javax.persistence.persistence;  [...] protected entitymanager manager;  protected final string tablename = "logentry";  public databaseimpl(db_type db) {     this.db = db;     if (entitymanagerfactory != null && entitymanagerfactory.isopen()) {         entitymanagerfactory.close();     }     entitymanagerfactory = persistence.createentitymanagerfactory(db.getpersunit());     manager = entitymanagerfactory.createentitymanager(); } public void insert(logentry entry) {      manager.gettransaction().begin();     manager.persist(entry);     manager.gettransaction().commit(); } 

but when try inserted values using method: public logentrylist getall() {

    manager.gettransaction().begin();      query query = manager.createnativequery("select * " + tablename + ";");     arraylist<logentry> entries = (arraylist<logentry>) query.getresultlist();     manager.gettransaction().commit();      return new logentrylist(entries); } 

i exception: java.lang.classcastexception: [ljava.lang.object; cannot cast de.motza.entities.logentry

i know problem casting of query result object, can't find anywhere how cast objects properly, or how more 1 row table.

does have advice? if requested, can post persistence.xml , more code

becuase have used nativequery need transfer result using setresulttransormer method.

    query query = manager.createnativequery("select * " + tablename + ";");     query.setresulttransformer(transformers.aliastobean(logentry.class))     arraylist<logentry> entries = (arraylist<logentry>) query.getresultlist();