bash - Variable variable assignment error -"command not found" -

when run script following errors. doing wrong here please? appreciated- bash newbie

error:

line 12: 0=1: command not found line 13: 0=1: command not found 

my script:

count_raw=0 avg_raw=0  $count_raw=1 $avg_raw=1  echo "count_raw=$count_raw" echo "avg_raw=$avg_raw" 

= assignment operator when found free , $ holds value (not in usa in bash too) of variable.

so when say: $var=1, you're trying type random string (0=1 in case) in bash , bash doesn't that. @ one-liner below shows 1 example you'd type in $var=1 , bash able process it:

var=1; if [[ $var=1 ]]; printf "congrats! have learned difference between variable assignment , variable comparison in ${var}st attempt.\n"; fi;